Solar Eclipse

[Jedi4Yahweh]

How can the shadow of the moon be so much smaller than the moon itself?  When you put an object in front of a light source the umbra (darker inner shadow) is always far bigger than the actual object.  Show me a real world experiment where the umbra (inner shadow) is smaller than the actually object being projected.  Before you go on about penumbra, I know that every shadow has a penumbra which is a outer thin hazy shadow where the shadow is diffusing with the surrounding light, but when they use it to explain the solar eclipses the penumbra is not a thin layer but a massively thicker layer that far exceeds the thickness of the actual shadow of the moon is projecting.  This does not happen in real world experiments.  Try it and see.

Edited April 2 by Jedi4Yahweh

[Who me]

The answer is very simple.

The Sun is so much more massive  than the moon that the shadow it casts is far smaller.

Imagine a cone, the sun is the base and the cone is light travelling  to the moon, the end of the cone represents the shadow, which is much smaller.ler.

If you don't  understand my explanation look at a professional  astrominers 3xp.anation at aig.

https://answersingenesis.org/blogs/danny-faulkner/2017/08/15/odds-and-ends-about-eclipse/

 

You'll  have to read a bit to find his exp,anation.

[Jedi4Yahweh]

12 hours ago, Who me said:

The answer is very simple.

The Sun is so much more massive  than the moon that the shadow it casts is far smaller.

Its not that simple. Here is a scenario, so when Sun is at high noon and a large jet fly's overhead the shadow (umbra) of the jet on the ground is massively larger than the actual jet.   How does that compute with what you just said?

[other one]

37 minutes ago, Jedi4Yahweh said:

Its not that simple. Here is a scenario, so when Sun is at high noon and a large jet fly's overhead the shadow (umbra) of the jet on the ground is massively larger than the actual jet.   How does that compute with what you just said?

I don't think an airplane is large enough to cast an Umbra.  It never blocks all the sun's light.

[Marathoner]

That hypothetical airplane fails to meet the following criteria:

1. It is not spherical in shape with a diameter of 2,159 miles;

2. It is not 238,900 miles away from the earth.

What meets the above criteria? The Moon. 

[Jedi4Yahweh]

39 minutes ago, other one said:

I don't think an airplane is large enough to cast an Umbra.  It never blocks all the sun's light.

In the same way neither does the moon block the sun for the entire earth only for certain areas and only for a very short time.  The dark strip that across America is the umbra.  The shadow of the plane that crosses the ground is the umbra.   

Edited April 2 by Jedi4Yahweh

[Jedi4Yahweh]

54 minutes ago, Marathoner said:

That hypothetical airplane fails to meet the following criteria:

1. It is not spherical in shape with a diameter of 2,159 miles;

2. It is not 238,900 miles away from the earth.

What meets the above criteria? The Moon. 

That makes no sense. The farther away an object is from the surface that it is projected on the large the shadow will be not smaller. A jet parked on the ground is going to have a shadow relatively close to its actual size.  Put that jet up in the sky the shadow will be much bigger on the ground.  It does not matter if it is spherical or a triangle a shadow is a shadow. 

Edited April 2 by Jedi4Yahweh

[other one]

43 minutes ago, Jedi4Yahweh said:

In the same way neither does the moon block the sun for the entire earth only for certain areas and only for a very short time.  The dark strip that across America is the umbra.  The shadow of the plane that crosses the ground is the umbra.   

To make an umbra, the entire surface of the sun must be blocked out. Maybe if the airplane was ten feet overhead, it might be considered one.  I don't see how one could have an umbra without blocking out the whole sun.     It does make a difference that the plane isn't 200,000 miles away.

[Marathoner]

40 minutes ago, Jedi4Yahweh said:

That makes no sense. The farther away an object is from the surface that it is projected on the large the shadow will be not smaller. A jet parked on the ground is going to have a shadow relatively close to its actual size.  Put that jet up in the sky the shadow will be much bigger on the ground.  It does not matter if it is spherical or a triangle a shadow is a shadow. 

That's not what happens, my friend. The more distant an object casting a shadow is from a location impacted by the umbra, the smaller that umbra becomes in relation to the actual size of the object casting that shadow. That's the observed effect. 

You have to duplicate the conditions of a solar eclipse in order to prove physicists wrong. Go for it. 

[Jedi4Yahweh]

10 minutes ago, other one said:

To make an umbra, the entire surface of the sun must be blocked out. Maybe if the airplane was ten feet overhead, it might be considered one.  I don't see how one could have an umbra without blocking out the whole sun.     It does make a difference that the plane isn't 200,000 miles away.

If you are standing in the shadow of the plane then the sun is being blocked entirely by the plane.  If you are standing outside the shadow of the plane then no the sun is not being entirely blocked.  In the same way someone in Texas is in the shadow of the eclipse, but someone in Arizona at that same time can see the Sun.